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1. (BH 4.7) A certain small town, whose population consists of 100 families, has 30

families with 1 child, 50 families with 2 children, and 20 families with 3 children.

The birth rank of one of these children is 1 if the child is the firstborn, 2 if the child

is the secondborn, and 3 if the child is the thirdborn.

(a) A random family is chosen (with equal probabilities), and then a random child

within that family is chosen (with equal probabilities). Find the PMF, mean, and

variance of the child’s birth rank.

(b) A random child is chosen in the town (with equal probabilities). Find the PMF,

mean, and variance of the child’s birth rank.

2. (BH 4.8) A certain country has four regions: North, East, South, and West.

The populations of these regions are 3 million, 4 million, 5 million, and 8 million,

respectively. There are 4 cities in the North, 3 in the East, 2 in the South, and there

is only 1 city in the West. Each person in the country lives in exactly one of these

cities.

(a) What is the average size of a city in the country? (This is the arithmetic mean

of the populations of the cities, and is also the expected value of the population of a

city chosen uniformly at random.)

Hint: Give the cities names (labels).

(b) Show that without further information it is impossible to find the variance of the

population of a city chosen uniformly at random. That is, the variance depends on

how the people within each region are allocated between the cities in that region.

(c) A region of the country is chosen uniformly at random, and then a city within

that region is chosen uniformly at random. What is the expected population size of

this randomly chosen city?

Hint: First find the selection probability for each city.

(d) Explain intuitively why the answer to (c) is larger than the answer to (a).

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3. (BH 4.19) Let X ∼ Bin(100, 0.9). For each of the following parts, construct an

example showing that it is possible, or explain clearly why it is impossible. In this

problem, Y is a random variable on the same probability space as X; note that X

and Y are not necessarily independent.

(a) Is it possible to have Y ∼ Pois(0.01) with P(X ≥ Y ) = 1?

(b) Is it possible to have Y ∼ Bin(100, 0.5) with P(X ≥ Y ) = 1?

(c) Is it possible to have Y ∼ Bin(100, 0.5) with P(X ≤ Y ) = 1?

4. (BH 4.25) Nick and Penny are independently performing independent Bernoulli

trials. For concreteness, assume that Nick is flipping a nickel with probability p1 of

Heads and Penny is flipping a penny with probability p2 of Heads. Let X1, X2, . . .

be Nick’s results and Y1, Y2, . . . be Penny’s results, with Xi ∼ Bern(p1) and Yj ∼

Bern(p2).

(a) Find the distribution and expected value of the first time at which they are

simultaneously successful, i.e., the smallest n such that Xn = Yn = 1.

Hint: Define a new sequence of Bernoulli trials and use the story of the Geometric.

(b) Find the expected time until at least one has a success (including the success).

Hint: Define a new sequence of Bernoulli trials and use the story of the Geometric.

(c) For p1 = p2, find the probability that their first successes are simultaneous, and

use this to find the probability that Nick’s first success precedes Penny’s.

5. (BH 4.34) Each of n ≥ 2 people puts his or her name on a slip of paper (no

two have the same name). The slips of paper are shuffled in a hat, and then each

person draws one (uniformly at random at each stage, without replacement). Find

the average number of people who draw their own names.

6. (BH 4.36) In a sequence of n independent fair coin tosses, what is the expected

number of occurrences of the pattern HT H (consecutively)? Note that overlap is

allowed, e.g., HT HT H contains two overlapping occurrences of the pattern.

7. (BH 4.43) You are being tested for psychic powers. Suppose that you do not

have psychic powers. A standard deck of cards is shuffled, and the cards are dealt

face down one by one. Just after each card is dealt, you name any card (as your

prediction). Let X be the number of cards you predict correctly. (See Diaconis

(1978) for much more about the statistics of testing for psychic powers.)

(a) Suppose that you get no feedback about your predictions. Show that no matter

what strategy you follow, the expected value of X stays the same; find this value.

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(On the other hand, the variance may be very different for different strategies. For

example, saying “Ace of Spades” every time gives variance 0.)

Hint: Indicator r.v.s.

(b) Now suppose that you get partial feedback: after each prediction, you are told

immediately whether or not it is right (but without the card being revealed). Suppose

you use the following strategy: keep saying a specific card’s name (e.g., “Ace of

Spades”) until you hear that you are correct. Then keep saying a different card’s

name (e.g., “Two of Spades”) until you hear that you are correct (if ever). Continue

in this way, naming the same card over and over again until you are correct and then

switching to a new card, until the deck runs out. Find the expected value of X, and

show that it is very close to e − 1.

Hint: Indicator r.v.s.

(c) Now suppose that you get complete feedback: just after each prediction, the card

is revealed. Call a strategy “stupid” if it allows, e.g., saying “Ace of Spades” as a

guess after the Ace of Spades has already been revealed. Show that any non-stupid

strategy gives the same expected value for X; find this value.

Hint: Indicator r.v.s.

8. (BH 4.66) Use Poisson approximations to investigate the following types of coincidences.

The usual assumptions of the birthday problem apply, such as that there

are 365 days in a year, with all days equally likely.

(a) How many people are needed to have a 50% chance that at least one of them has

the same birthday as you?

(b) How many people are needed to have a 50% chance that there are two people

who not only were born on the same day, but also were born at the same hour (e.g.,

two people born between 2 pm and 3 pm are considered to have been born at the

same hour).

(c) Considering that only 1/24 of pairs of people born on the same day were born

at the same hour, why isn’t the answer to (b) approximately 24 · 23? Explain this

intuitively, and give a simple approximation for the factor by which the number of

people needed to obtain probability p of a birthday match needs to be scaled up to

obtain probability p of a birthday-birthhour match.

(d) With 100 people, there is a 64% chance that there are 3 with the same birthday

(according to R, using pbirthday(100,classes=365,coincident=3) to compute

it). Provide two different Poisson approximations for this value, one based on creating

an indicator r.v. for each triplet of people, and the other based on creating an

indicator r.v. for each day of the year. Which is more accurate?

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